Use Sentinel-2A images with Python (ArcPy)

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11-11-2021 07:47 AM
Diego_Mendes_Rodrigues
New Contributor II

Colleagues,

I need to access Sentinel-2 Level-2A images from Esri's Living Atlas of The World using ArcPy.
(https://imagem.maps.arcgis.com/home/item.html?id=255af1ceee844d6da8ef8440c8f90d00)

If I cannot access the Living Atlas images, what would be another alternative?

The Sentinel-2 image I access needs to be with a certain objectid, example objectid: 23156221.

What should the code in ArcPy (or Python) look like for me to use Sentinel-2 images?

Thanks!

Diego

 

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DonMorrison1
Occasional Contributor III

I wasn't able to access the layer from arcpy - I'm not sure why. But an alternative is to use the  ArcGIS API for python.  The code to access your object would look like this ('255af1ceee844d6da8ef8440c8f90d00' is the ArcGIS item ID for the sentinal image layer):

from arcgis.gis import GIS

gis = GIS(url=None, username=<my_id>, password=<my_pw>)
item = gis.content.get('255af1ceee844d6da8ef8440c8f90d00')
record = item.layers[0].query(where="objectid=23156221").to_dict()['features'][0]
print (record)

 

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DonMorrison1
Occasional Contributor III

I wasn't able to access the layer from arcpy - I'm not sure why. But an alternative is to use the  ArcGIS API for python.  The code to access your object would look like this ('255af1ceee844d6da8ef8440c8f90d00' is the ArcGIS item ID for the sentinal image layer):

from arcgis.gis import GIS

gis = GIS(url=None, username=<my_id>, password=<my_pw>)
item = gis.content.get('255af1ceee844d6da8ef8440c8f90d00')
record = item.layers[0].query(where="objectid=23156221").to_dict()['features'][0]
print (record)

 

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Diego_Mendes_Rodrigues
New Contributor II

How can I download this service's image using Python?

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