Convert json.simplify to CSV

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03-07-2019 06:48 AM
jaykapalczynski
Frequent Contributor

I have a return from a query that I am pushing to a dgrid.  That works fine.

I want to take this json return and convert it to .csv  I tried the code below and sent to an alert and it puts a comman after each character???

json simplify:

var json = JSONObject;	 // This is my json object as seen in the image above	
var csv = "";
		
function toCSV(json) {
	alert("In Function");
	json = Object.values(json);
	var keys = (json[0] && Object.keys(json[0])) || [];
	csv += keys.join(',') + '\n';
	for (var line of json) {
	    csv += keys.map(key => line[key]).join(',') + '\n';
	}
	return csv;
}

toCSV(json);
alert(csv);

This is the return I get when I alert the CSV variable....

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Accepted Solutions
jaykapalczynski
Frequent Contributor

Think I got it....

function ConvertToCSV2(objArray) {
    let rows = typeof objArray !== "object" ? JSON.parse(objArray) : objArray;
    let  header = "";
    Object.keys(rows[0]).map(pr => (header += pr + ","));

    let str2 = "";
    rows.forEach(row => {
        let line = "";
        let columns =
            typeof row !== "object" ? JSON.parse(row) : Object.values(row);
        columns.forEach(column => {
            if (line !== "") {
                line += ",";
            }
            if (typeof column === "object") {
                line += JSON.stringify(column);
            }  else {
                line += column;
            }
        });
        str2 += line + "\r\n";
    });
    return header + "\r\n" + str2;
}

// Grab my Json return from the query and send to function
var RailroadCSVObject2 = ConvertToCSV2(RailroadJSONObject);
		
// Grab the value and export a csv file for the user.
var pom = document.createElement('a');
var csvContent=RailroadCSVObject2; //here we load our csv data 
var blob = new Blob([csvContent],{type: 'text/csv;charset=utf-8;'});
var url = URL.createObjectURL(blob);
pom.href = url;
pom.setAttribute('download', 'DataExport.csv');
pom.click();

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3 Replies
jaykapalczynski
Frequent Contributor

If I do this I get a decent return but no headers.....how do I add the headers to this final output of this

// JSON to CSV Converter
function ConvertToCSV(objArray) {
   var array = typeof objArray != 'object' ? JSON.parse(objArray) : objArray;
   var str = '';
			
   for (var i = 0; i < array.length; i++) {
       var line = '';
       for (var index in array[i]) {
           if (line != '') line += ','

           line += array[i][index];
       }

       str += line + '\r\n';
    }

    return str;
}‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍


var RailroadCSVObject = ConvertToCSV(RailroadJSONObject);

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jaykapalczynski
Frequent Contributor

Think I got it....

function ConvertToCSV2(objArray) {
    let rows = typeof objArray !== "object" ? JSON.parse(objArray) : objArray;
    let  header = "";
    Object.keys(rows[0]).map(pr => (header += pr + ","));

    let str2 = "";
    rows.forEach(row => {
        let line = "";
        let columns =
            typeof row !== "object" ? JSON.parse(row) : Object.values(row);
        columns.forEach(column => {
            if (line !== "") {
                line += ",";
            }
            if (typeof column === "object") {
                line += JSON.stringify(column);
            }  else {
                line += column;
            }
        });
        str2 += line + "\r\n";
    });
    return header + "\r\n" + str2;
}

// Grab my Json return from the query and send to function
var RailroadCSVObject2 = ConvertToCSV2(RailroadJSONObject);
		
// Grab the value and export a csv file for the user.
var pom = document.createElement('a');
var csvContent=RailroadCSVObject2; //here we load our csv data 
var blob = new Blob([csvContent],{type: 'text/csv;charset=utf-8;'});
var url = URL.createObjectURL(blob);
pom.href = url;
pom.setAttribute('download', 'DataExport.csv');
pom.click();

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RobertScheitlin__GISP
MVP Esteemed Contributor

Jay,

  Does your objArray have the header info?

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