Why esriSpatialRelTouches relation does not work?

Discussion created by demdemeleeds on Jan 29, 2012
Latest reply on Jan 30, 2012 by demdemeleeds
I have two feature layers. The first one is just a polygon and the other one consists of a series of polygons which are enclosed by the first one. Thus, some polygons of the second feature layer touch on the boundaries of the first feauture layer. I wrotre a code (the basic part shown below to identify which polygons of the second layer touches the boundary of the polygon in the first layer but while the code runs without a problem it does not identify (e.g. by giving FID with Msgbox) any such polygon whilsty it should.
Any help please?

    Dim pBlockBoundaryFC  As IFeatureClass
    Set pBlockBoundaryFC = pBlockBoundary.FeatureClass

    Dim pBlockBoundaryFields  As IFields
    Set pBlockBoundaryFields = pBlockBoundaryFC.Fields

    Dim pGeom As IGeometry

    Dim pSpatialFilter As ISpatialFilter
    Set pSpatialFilter = New SpatialFilter

    Dim pBlockBoundaryCursor As IFeatureCursor
    Set pBlockBoundaryCursor = pBlockBoundaryFC.Search(pSpatialFilter, False)

    Set pBlockBoundaryFeature = pBlockBoundaryCursor.NextFeature
    Do Until pBlockBoundaryFeature Is Nothing

    Set pGeom = pBlockBoundaryFeature.Shape
    With pSpatialFilter
    Set .Geometry = pGeom
        .GeometryField = "Shape"
        .SpatialRel = esriSpatialRelTouches
    End With

    Dim pRelOp As IRelationalOperator
    Set pRelOp = pGeom

      Set pNewParcelsFeature = pNewParcelsCursor.NextFeature
      Do Until pNewParcelsFeature Is Nothing

        FID = pNewParcelsFeature.Value(intposFID)
        If pRelOp.Touches(pNewParcelsFeature.Shape) Then

        ''Report the FID of each parcel that 'touches' the exetrnal boundary
        MsgBox FID
        End If
    Set pNewParcelsFeature = pNewParcelsCursor.NextFeature


    Set pBlockBoundaryFeature = pBlockBoundaryCursor.NextFeature