I was also having this problem with publishing my map through ArcGIS Pro (2.9.5) to ArcGIS Enterprise (10.8.1). This was trying to publish a map service to my federated server.
Instead of deleting all my settings (although I do like to do this from time to time to clean things up), I created a little script that will create the sddraft, sd and publish to my federated server. I thought I would share this (run this from the python window in ArcGIS Pro and signed in to your Portal). One thing I noticed is that the item is not created in the "portal_folder_name" that is set, it just creates it in the user's root folder for Portal.
import os
portal_url = "https://[domain_name]/portal"
federated_server_url = "https://[domain_name]/server"
portal_folder_name = "Planning"
server_folder_name = "Planning"
aprx = arcpy.mp.ArcGISProject("CURRENT")
m = aprx.listMaps(aprx.activeMap.name)[0]
sd_draft_file_path = os.path.join(os.path.dirname(aprx.filePath), m.name + ".sddraft")
sd_file_path = sd_draft_file_path.replace(".sddraft", ".sd")
service_name = m.name
server_type = "FEDERATED_SERVER"
print(f"Creating SD Draft file: \"{sd_draft_file_path}\"")
tags = ""
if m.metadata.tags:
tags = ", ".join([tag_list.strip()for tag_list in m.metadata.tags.split(",")])
sddraft = m.getWebLayerSharingDraft(server_type, "MAP_IMAGE", service_name)
sddraft.federatedServerUrl = federated_server_url
sddraft.credits = m.metadata.credits
sddraft.description = m.metadata.description
sddraft.summary = m.metadata.summary
sddraft.tags = tags
sddraft.portalFolder = portal_folder_name
sddraft.serverFolder = server_folder_name
try:
sddraft.exportToSDDraft(sd_draft_file_path)
except Exception as err:
print(f"ERROR: {err}".replace("\n", " "))
print(f"Creating SD file: {sd_file_path}")
try:
arcpy.server.StageService(sd_draft_file_path, sd_file_path)
except Exception as err:
print(f"ERROR: {err}".replace("\n", " "))
# Share to portal
print(f"Uploading service to {federated_server_url}...")
try:
arcpy.server.UploadServiceDefinition(sd_file_path, federated_server_url)
except Exception as err:
print(f"ERROR: {err}".replace("\n", " "))
). Thanks again!
