topic Re: Parse EXIF with Time Module in Python Questions

Parse EXIF with Time Module

JaredPilbeam2 — Sat, 11 Dec 2021 06:19:35 GMT

I'm attempting to extract the Date Taken from jpgs within a directory. And then I want to have the date printed as such: mo/day/year

Here's an example of a JPG's Properties menu:

This code runs with no error but the output isn't what I want.

import exifread
from exifread import exif
import os
import time

im = r"path\to\DOT_SignInventory"

for root, dirnames, filenames in os.walk(im):
    for fname in filenames:
        if fname.endswith('.JPG'):
            with open(os.path.join(root, fname), 'rb') as image: #file path and name
                exif = exifread.process_file(image)
                dt = str(exif['EXIF DateTimeOriginal'])  #get Date Taken from JPG
                date = time.strptime(dt, '%Y:%m:%d %H:%M:%S')
                print("Photo:{} Date Taken:{}".format(fname, date))‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Photo:0710100.JPG Date Taken:time.struct_time(tm_year=2018, tm_mon=6, tm_mday=5, tm_hour=13, tm_min=49, tm_sec=40, tm_wday=4, tm_yday=166, tm_isdst=-1)‍‍‍

Ideally, I want the output to look as such:

Photo:0710100.JPG Date Taken:06/05/2018‍‍‍‍‍

For line 14, I can't find the right format. I've also tried the datetime module but couldn't get that to work right either.

Re: Parse EXIF with Time Module

RandyBurton — Sat, 11 Dec 2021 06:19:38 GMT

Try:

st = '2018:06:05 13:49:40'
dt = time.strptime(st, '%Y:%m:%d %H:%M:%S')
print time.strftime("%m/%d/%Y",dt)‍‍‍

I was experimenting with some exif code in my answers in this thread which may be of interest.

Re: Parse EXIF with Time Module

JaredPilbeam2 — Sat, 11 Dec 2021 06:19:41 GMT

Randy,

Thanks, that helped. As it stands, it only reads the first JPG, which has the date 04/27/2018. It isn't printing the dates of the numerous other files?

im = r"path\to\DOT_SignInventory"

for root, dirnames, filenames in os.walk(im):
    for fname in filenames:
        if fname.endswith('.JPG'):
            with open(os.path.join(root, fname), 'rb') as image: #file path and name
                exif = exifread.process_file(image)
                dt = str(exif['EXIF DateTimeOriginal'])#get JPG 'Date taken'
                st = '2018:04:27 09:30:59'
                date = time.strptime(st, '%Y:%m:%d %H:%M:%S')
                print(time.strftime("%m/%d/%Y",date))‍‍‍‍‍‍‍‍‍‍‍

04/27/2018
04/27/2018
04/27/2018
04/27/2018
04/27/2018
04/27/2018‍‍‍‍‍‍
etc...‍‍‍‍‍‍‍

It seems the first part of the code involving exif (up to line 😎 works fine. If I put a print statement after line 8:

print(dt)‍

it gives me:

2018:04:27 09:30:59
2018:04:27 09:36:30
2018:04:27 09:40:00
2018:04:27 09:41:03
2018:04:27 09:42:03
2018:04:27 09:47:00‍‍‍‍‍‍
etc...‍‍‍‍‍‍‍

Re: Parse EXIF with Time Module

RandyBurton — Sat, 11 Dec 2021 06:19:44 GMT

You should delete line 9 in your last code sample, and then adjust the variable name in line 10. Try something like:

for root, dirnames, filenames in os.walk(im):
    for fname in filenames:
        if fname.endswith('.JPG'):
            with open(os.path.join(root, fname), 'rb') as image: #file path and name
                exif = exifread.process_file(image)
                dt = str(exif['EXIF DateTimeOriginal'])#get JPG 'Date taken'
                ds = time.strptime(dt, '%Y:%m:%d %H:%M:%S')
                print(time.strftime("%m/%d/%Y",ds))‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Also, I try to avoid using variable names like date and time as they sometimes can conflict with items in the include modules (instead I use dt for datetime and ds for datestring, for example).