topic Re: Simple Python label expression FAIL! in Python Questions

Simple Python label expression FAIL!

KevinBell1 — Mon, 17 Mar 2025 16:44:24 GMT

In the python window, this works as expected:

n = 1313.87
type(n)
<class 'float'>
str(n).split('.')[1]
'87'

HOWEVER, trying to do the same to label features fails:

Note that PtZ is a Double, and the label expression str([PtZ]) labels just fine.

What am I doing wrong here???

Pro version 3.4

Re: Simple Python label expression FAIL!

CodyPatterson — Mon, 17 Mar 2025 17:08:45 GMT

Hey @KevinBell1

It looks like when using the label expressions, it's placing a "return" in front of the expression. This normally means you will need to create a function for this, with set return values, something like this here:

def FindLabel([PtZ]): val = str([PtZ]) parts = val.split('.') if len(parts) > 1: return parts[1] else: return ''

Let me know if this ends up working for you!

Cody

Re: Simple Python label expression FAIL!

JoshuaBixby — Mon, 17 Mar 2025 17:17:11 GMT

It can be simplified a bit more even. The [PtZ] doesn't have to be stored in a separate variable, it is already a variable:

def FindLabel([PtZ]): return [PtZ].split('.')[1]

Re: Simple Python label expression FAIL!

KevinBell1 — Wed, 26 Mar 2025 18:19:06 GMT

Great! That works, but is some weird ESRI stuff going on since you can't split a float/double!