topic Re: [bug?]Layers with the same name are not distinguished in Python Questions

[bug?]Layers with the same name are not distinguished

-_- — Mon, 29 Jul 2024 05:42:14 GMT

I created a code that gets multiple layers from the parameters and makes them visible.

import arcpy selectLayerLists=arcpy.GetParameterAsText(0) #LayerList aprx=arcpy.mp.ArcGISProject("CURRENT") lay=aprx.activeView #Layout mf=lay.listElements("mapframe_element","*")[0] map=mf.map Lyr_list=selectLayerLists.split(";") arcpy.AddMessage(Lyr_list) for lyr in Lyr_list: map.listLayers(lyr)[0].visible=True

Layer structure:
ryoho
ryoho/L02
ryoho/L01
L02
L01

The layer selected as the parameter:
ryoho
L02
L01

Code execution results:

As shown in the image, the group layer and layers with the same name within the group have been switched to display.
How can you get the results you want with the parameters?

As an experiment, I retrieved the parameters with "GetParameter" and set the retrieved layer.visible=True, but the layer did not appear.
In 3.2.2, layers with the same name were distinguished as "Layer1:1" and "Layer1:2", so this code worked without any problems, but after updating to 3.3.1, the following situation occurred.

Due to the nature of my work, there are many layers with the same name, and changing the layer names for the sake of creating legends is not a good idea.
I would appreciate any ideas on how to solve this problem.
I would also like to know if this problem is only occurring in my environment.

Re: [bug?]Layers with the same name are not distinguished

TonyAlmeida — Wed, 31 Jul 2024 17:27:40 GMT

Maybe specify the group layer name?

import arcpy # Define the path to the project and the map aprx_path = r'C:\path\project.aprx' map_name = 'Map' group_layer_to_turn_on = 'YourGroupLayerName' # Specify the name of the group layer # Open the project aprx = arcpy.mp.ArcGISProject(aprx_path) # Get the map m = aprx.listMaps(map_name)[0] # Function to turn on a specific group layer and its sub-layers recursively def turn_on_specific_group_layer(layer, group_layer_name): if layer.isGroupLayer and layer.name == group_layer_name: layer.visible = True print(f"Turned on visibility for group layer: {layer.name}") for sub_layer in layer.listLayers(): turn_on_sub_layers(sub_layer) # Recursively check sub-layers # Function to turn on all sub-layers of a specific group layer def turn_on_sub_layers(layer): if layer.isGroupLayer: layer.visible = True print(f"Turned on visibility for sub-group layer: {layer.name}") for sub_layer in layer.listLayers(): turn_on_sub_layers(sub_layer) # Recursively check sub-layers else: layer.visible = True print(f"Turned on visibility for sub-layer: {layer.name}") # Loop through top-level layers in the map to find the specific group layer for lyr in m.listLayers(): turn_on_specific_group_layer(lyr, group_layer_to_turn_on) # Save the project #aprx.save() #print("Project saved.") # Clean up #del aprx

Re: [bug?]Layers with the same name are not distinguished

AlfredBaldenweck — Thu, 01 Aug 2024 13:35:29 GMT

Give longName a shot, that will include if it's in a group layer or not. You'll probably just have to do it as a check of some sort, like

"if '\\'in lay.longName"

Re: [bug?]Layers with the same name are not distinguished

-_- — Fri, 09 Aug 2024 02:24:12 GMT

Thank you for the idea.

However, since I need to get the layer name as a parameter, it's a pain to specify the group name each time.

So I decided to temporarily process it using the index number until it returns to normal.

import arcpy selectLayerLists=arcpy.GetParameterAsText(0) #レイヤリスト aprx=arcpy.mp.ArcGISProject("CURRENT") lay=aprx.activeView mf=lay.listElements("mapframe_element","*")[0] map=mf.map allLayerList=map.listLayers() allLayerList_index=[] Lyr_list=selectLayerLists.split(";") #レイヤ名をリストに分割 for i in range(0,len(allLayerList)): allLayerList_index.append([i,map.listLayers()[i].longName]) arcpy.AddMessage(allLayerList_index) for n in range(0,len(allLayerList_index)): arcpy.AddMessage(allLayerList_index[n][1]) if allLayerList_index[n][1] in Lyr_list: targetNumber=allLayerList_index[n][0] map.listLayers()[targetNumber].visible=False