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    <title>topic Re: Pandas Styler in Python Questions</title>
    <link>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203900#M65354</link>
    <description>&lt;P&gt;&lt;a href="https://community.esri.com/t5/user/viewprofilepage/user-id/557852"&gt;@dslamb2022&lt;/a&gt;&amp;nbsp;et al,&lt;/P&gt;&lt;P&gt;In the same vein, do you have any notion of how to set conditional formatting based on another column?&amp;nbsp; Let's say we have...&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="TylerT_0-1660762395172.png" style="width: 400px;"&gt;&lt;img src="https://community.esri.com/t5/image/serverpage/image-id/48857iAFD4319C9B35BF4F/image-size/medium?v=v2&amp;amp;px=400" role="button" title="TylerT_0-1660762395172.png" alt="TylerT_0-1660762395172.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;and we want to produce this...&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="TylerT_1-1660762475625.png" style="width: 400px;"&gt;&lt;img src="https://community.esri.com/t5/image/serverpage/image-id/48858i262A579A09236A60/image-size/medium?v=v2&amp;amp;px=400" role="button" title="TylerT_1-1660762475625.png" alt="TylerT_1-1660762475625.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;where: if value in col 0 == 'A' then format float as '{:.3f}f' and if col 0 == 'B' then format as&amp;nbsp;'{:.3f}m', using&amp;nbsp;df.style.format() or other formatting/styler methods.&lt;/P&gt;&lt;P&gt;Thank you,&lt;/P&gt;&lt;P&gt;Tyler&lt;/P&gt;</description>
    <pubDate>Wed, 17 Aug 2022 19:00:12 GMT</pubDate>
    <dc:creator>TylerT</dc:creator>
    <dc:date>2022-08-17T19:00:12Z</dc:date>
    <item>
      <title>Pandas Styler</title>
      <link>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203800#M65351</link>
      <description>&lt;P&gt;I'm trying to pass conditional string formatting from a function back to style.format as shown here....&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="TylerT_0-1660752488025.png" style="width: 400px;"&gt;&lt;img src="https://community.esri.com/t5/image/serverpage/image-id/48830i8A7BAAF0AE51DDE6/image-size/medium?v=v2&amp;amp;px=400" role="button" title="TylerT_0-1660752488025.png" alt="TylerT_0-1660752488025.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;Ultimately, I'm looking for the same results as above EXCEPT&amp;nbsp;&lt;SPAN&gt;{:.3f}m should be 3.000m in the output displayed dataframe.&amp;nbsp; Any ideas?&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;Thank you,&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;Tyler&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&lt;SPAN&gt;Here's the code for testing:&lt;/SPAN&gt;&lt;/P&gt;&lt;LI-CODE lang="python"&gt;df = pd.DataFrame([[np.nan, 1.0, 'A'], [2.0, np.nan, 3.0]])
df
func = lambda s: 'STRING' if isinstance(s, str) else '{:.3f}m'
df.style.format({0: '{:.3f}m', 2: func}, na_rep='MISS')&lt;/LI-CODE&gt;</description>
      <pubDate>Wed, 17 Aug 2022 16:21:20 GMT</pubDate>
      <guid>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203800#M65351</guid>
      <dc:creator>TylerT</dc:creator>
      <dc:date>2022-08-17T16:21:20Z</dc:date>
    </item>
    <item>
      <title>Re: Pandas Styler</title>
      <link>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203824#M65352</link>
      <description>&lt;P&gt;I think you are missing the format function.&amp;nbsp;&lt;/P&gt;&lt;LI-CODE lang="python"&gt;'{:.3f}m'.format(s)&lt;/LI-CODE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Wed, 17 Aug 2022 16:58:13 GMT</pubDate>
      <guid>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203824#M65352</guid>
      <dc:creator>dslamb2022</dc:creator>
      <dc:date>2022-08-17T16:58:13Z</dc:date>
    </item>
    <item>
      <title>Re: Pandas Styler</title>
      <link>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203842#M65353</link>
      <description>&lt;P&gt;Thank you!&lt;/P&gt;</description>
      <pubDate>Wed, 17 Aug 2022 17:14:15 GMT</pubDate>
      <guid>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203842#M65353</guid>
      <dc:creator>TylerT</dc:creator>
      <dc:date>2022-08-17T17:14:15Z</dc:date>
    </item>
    <item>
      <title>Re: Pandas Styler</title>
      <link>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203900#M65354</link>
      <description>&lt;P&gt;&lt;a href="https://community.esri.com/t5/user/viewprofilepage/user-id/557852"&gt;@dslamb2022&lt;/a&gt;&amp;nbsp;et al,&lt;/P&gt;&lt;P&gt;In the same vein, do you have any notion of how to set conditional formatting based on another column?&amp;nbsp; Let's say we have...&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="TylerT_0-1660762395172.png" style="width: 400px;"&gt;&lt;img src="https://community.esri.com/t5/image/serverpage/image-id/48857iAFD4319C9B35BF4F/image-size/medium?v=v2&amp;amp;px=400" role="button" title="TylerT_0-1660762395172.png" alt="TylerT_0-1660762395172.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;and we want to produce this...&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="TylerT_1-1660762475625.png" style="width: 400px;"&gt;&lt;img src="https://community.esri.com/t5/image/serverpage/image-id/48858i262A579A09236A60/image-size/medium?v=v2&amp;amp;px=400" role="button" title="TylerT_1-1660762475625.png" alt="TylerT_1-1660762475625.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;where: if value in col 0 == 'A' then format float as '{:.3f}f' and if col 0 == 'B' then format as&amp;nbsp;'{:.3f}m', using&amp;nbsp;df.style.format() or other formatting/styler methods.&lt;/P&gt;&lt;P&gt;Thank you,&lt;/P&gt;&lt;P&gt;Tyler&lt;/P&gt;</description>
      <pubDate>Wed, 17 Aug 2022 19:00:12 GMT</pubDate>
      <guid>https://community.esri.com/t5/python-questions/pandas-styler/m-p/1203900#M65354</guid>
      <dc:creator>TylerT</dc:creator>
      <dc:date>2022-08-17T19:00:12Z</dc:date>
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