topic How to overwrite the contents of an element in service definition draft file ? in Python Questions

How to overwrite the contents of an element in service definition draft file ?

RehanChaudhary — Wed, 19 Jan 2022 15:22:00 GMT

I am trying to overwrite the default metadata stored in the service definition draft file under the "XmlDoc" element tag. The problem that i am facing is that when i overwrite it ,my file changes into the standard xml file probably because of the library and workflow that i am using for changing it. How can i do it without changing the actual structure of draft file?

Here is how i do it:

import xml.etree.ElementTree as ET import os import sys import json import arcgisscripting import arcpy import arcgis from arcgis.gis import GIS import xml.dom.minidom as DOM import shutil import xml.etree.ElementTree as ET import netCDF4 import lxml.etree as et rasterimage = r"C:\Users\arcgis\schism.crf" output_draft = r"C:\Users\arcgis\airquality.sddraft" service = "airquality" con = r"C:\Users\arcgis\rasterimage.ags" arcpy.CreateImageSDDraft(rasterimage, output_draft, service, 'FROM_CONNECTION_FILE', con, True, None, "netCDF test", "schism,netcdf") metadata_path=r"C:\Users\arcgis\UnidataDD2MI_result.xml" xsl_file=r"C:\Users\arcgis\MyScript.xsl" out_file=r"C:\Users\arcgis\out.xml" doc = et.parse(output_draft) xsl = et.parse(xsl_file) transform = et.XSLT(xsl) result = transform(doc) print(result) result.write_output(out_file) sys.exit(0)

The xsl file looks like this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="yes" encoding="utf-8" indent="yes" /> <xsl:strip-space elements="*"/>  <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template>  <xsl:template match="XmlDoc"> <xsl:copy> <xsl:apply-templates select="document('UnidataDD2MI_result.xml')"/> </xsl:copy> </xsl:template> </xsl:stylesheet>

Re: How to overwrite the contents of an element in service definition draft file ?

AzinSharaf — Wed, 19 Jan 2022 17:30:22 GMT

use xml.dom.minidom instead.

This is code snippet I used to modify the service definition file. You can tweak it based on your needs.

import xml.dom.minidom as dom doc = dom.parse(sddraft_output_filename) # Find all elements named TypeName. This is where the server object extension # (SOE) names are defined. typeNames = doc.getElementsByTagName('TypeName') for typeName in typeNames: # Get the TypeName we want to enable. if typeName.firstChild.data == "FeatureServer": extension = typeName.parentNode for extElement in extension.childNodes: # Enable Feature Access. if extElement.tagName == 'Enabled': extElement.firstChild.data = 'true' # Output to a new sddraft. sddraft_mod_xml = service + '_mod_xml' + '.sddraft' sddraft_mod_xml_file = os.path.join(sddraft_folder, sddraft_mod_xml) f = open(sddraft_mod_xml_file, 'w') doc.writexml(f) f.close()

Re: How to overwrite the contents of an element in service definition draft file ?

RehanChaudhary — Wed, 19 Jan 2022 17:40:46 GMT

@AzinSharaf i don't think minidom can be used for replacing elemtns in service definition file. as you have worked with it, i will explain it in detail whjat i want to do. i have an xml file which contains metadat and i want this to be integrated into the service definition file in the "XmlDoc" tag. if you see the service definition file, you will see it contains a "Xml Doc" tag right at the end. is there a possibility of doing it with minidom?

Re: How to overwrite the contents of an element in service definition draft file ?

AzinSharaf — Wed, 19 Jan 2022 18:23:51 GMT

do you need a modified sddraft as an output file? Can you use this?

out_file=r"C:\Users\arcgis\out.sddraft"

Re: How to overwrite the contents of an element in service definition draft file ?

RehanChaudhary — Mon, 24 Jan 2022 08:32:12 GMT

@AzinSharaf yes i need a modified sddraft as an output file but the above statement that you have mentioned is not working. When i use the above statement it changes the format of sddraft to something different and then i cannot enable WMS and feature service in the way that you have mentioned in your code and how i am also doing in following code:

xsl_file=r"C:\Users\Chaudhr1\arcgis\MyScript.xsl" out_file=r"C:\Users\Chaudhr1\arcgis\out.sddraft" doc = et.parse(output_draft) xsl = et.parse(xsl_file) transform = et.XSLT(xsl) result = transform(doc) print(result) result.write_output(out_file) soe = 'WMSServer' doc = DOM.parse(out_file) typeNames = doc.getElementsByTagName('TypeName') descriptions = doc.getElementsByTagName('Type') newType = 'esriServiceDefinitionType_Replacement' keys=doc.getElementsByTagName('Key') for key in keys: if key.hasChildNodes(): if key.firstChild.data == 'PackageIsPublic': key.nextSibling.firstChild.data = 'true'

is there a way that i create sddraft file only once and then modify it keeping its original format intact? i would appreciate any help