topic Re: Custom script tool parameters will not accept decimals in Python Questions

Custom script tool parameters will not accept decimals

JaredPilbeam2 — Mon, 18 Oct 2021 19:38:03 GMT

I have a script tool that sets a layer's break values and their labels. The user will also need to enter decimals as values. I can't seem to get the tool to do that. Here I have the break values set to accept a Long data type. I've also tried a double, and a string.

The break values entered into the tool are forced to be integers in the script.

#class break values classbreakvalues = sys.argv[1] #break value parameter entered here breakvalues_list = classbreakvalues.split(";") new_breakvalues_list = [] for brkvalues in breakvalues_list: newbreak = int(brkvalues) # integer value new_breakvalues_list.append(newbreak) classBreakValues = new_breakvalues_list

If I run the following, the tool won't accept a decimal value.

I get this error, which I understand to mean you can't have an string as an integer. But I don't see how that could be.

ValueError: invalid literal for int() with base 10: '70.5'

Re: Custom script tool parameters will not accept decimals

DanPatterson — Mon, 18 Oct 2021 20:43:51 GMT

classbreakvalues.split(";")

suggests that the values are being returned as a semicolon delimited string. If that is the cast them to a float when you get them.

vals = "40;45;70.5;100" v = vals.split(";") v0 = [float(i) for i in v] v ['40', '45', '70.5', '100'] v0 [40.0, 45.0, 70.5, 100.0]

Re: Custom script tool parameters will not accept decimals

Anonymous User — Mon, 18 Oct 2021 21:15:48 GMT

The int type can't have decimals so you need to use a float conversion if you want to persist the decimal values.

newbreak = float(brkvalues) # integer value

You can cast to float first then int, but it will truncate your number.

val = int(float(brkvalues))

Re: Custom script tool parameters will not accept decimals

JaredPilbeam2 — Wed, 20 Oct 2021 15:31:10 GMT

newbreak = [float(i) for i in brkvalues]

@DanPattersonIf I use that it gives me: TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'.

@Anonymous UserI used float(brkvalues) and set the tool Data Type to Double. The tool ran with no error, but the value I set to a decimal was not changed in the symbology. And yes, I've noticed newbreak = int(float(brkvalues)) doesn't show the decimal places in the symbology either.

Re: Custom script tool parameters will not accept decimals

JaredPilbeam2 — Tue, 19 Oct 2021 15:21:52 GMT

Using newbreak = float(brkvalues) also does something with the highest value in a particular field. I set the last upper break value to be 100 in the tool parameters before I ran it. But, for some reason its grabbing the highest value in a particular layer's table and setting it as the last upper value in the symbology. Here, for example, 69.57 is the highest value in the % Vaccinated - 14-16 field. It ignores my label and it shows a decimal?

Re: Custom script tool parameters will not accept decimals

DanPatterson — Tue, 19 Oct 2021 18:34:31 GMT

you have to int a float not a string, hence int(float("1.1")), but int("1") is ok (refer to type conversion docs in python)

Re: Custom script tool parameters will not accept decimals

JaredPilbeam2 — Wed, 20 Oct 2021 18:33:45 GMT

All three of the following arrangements in the code are successful when running them from the script tool. But, not one of them change the break value to a decimal in the layer's symbology. This leads me to believe something is up with the tool.

#Results in neither decimal in layer symbology nor print statement for brkvalues in breakvalues_list: newbreak = int(float(brkvalues)) arcpy.AddMessage(f'newbreak: {newbreak}') #prints these values #break value: 40 #break value: 45 #break value: 60 #break value: 100 #No decimal in layer symbology, but decimal in print statement for brkvalues in breakvalues_list: newbreak = float(brkvalues) arcpy.AddMessage(f'break value: {newbreak}') #prints these values #break value: 40 #break value: 45 #break value: 60.9 #break value: 100 #No decimal in layer symbology, but decimal in print statement from decimal import Decimal for brkvalues in breakvalues_list: newbreak = Decimal(brkvalues) arcpy.AddMessage(f'break value: {newbreak}') #prints these values #break value: 40 #break value: 45 #break value: 60.9 #break value: 100

Re: Custom script tool parameters will not accept decimals

JaredPilbeam2 — Wed, 20 Oct 2021 21:33:36 GMT

OK, I was too focused on one part of the script. The snippet I had posted above was the section of code that takes the users input and puts it into a variable. Then there is the other part of the script the assigns that input to the upperBound element of the symbology. This is what I needed to convert to a float! Thanks for your answers.

import arcpy, sys aprx = arcpy.mp.ArcGISProject('CURRENT') #make sure fields in list are in same order as maps in project fields = ['VaccPercentageTotPop', 'VaccPercentage11to14', 'VaccPercentage0to18', 'VaccPercentage12to18', 'VaccPercentage14to16', 'VaccPercentage16to18', 'VaccPercentage19to64', 'VaccPercentage65Plus'] c = 0 #use counter to give a number to each map in for loop for map in aprx.listMaps(): arcpy.AddMessage(f'--- map: {map.name} ---') layers = map.listLayers() for layer in layers: arcpy.AddMessage(f'layer: {layer.name}') sym = layer.symbology #Reset renderer sym.updateRenderer('SimpleRenderer') sym.updateRenderer('GraduatedColorsRenderer') if hasattr(sym, 'renderer') and layer.name.startswith('BaseLayer'): Renderer = sym.renderer Renderer.classificationField = fields[c] #class break values classbreakvalues = arcpy.GetParameterAsText(0) breakvalues_list = classbreakvalues.split(";") new_breakvalues_list = [] for brkvalues in breakvalues_list: newbreak = brkvalues arcpy.AddMessage(f'break value: {newbreak}') new_breakvalues_list.append(newbreak) classBreakValues = new_breakvalues_list #class break labels classbreaklabels = arcpy.GetParameterAsText(1) breaklabels_list = classbreaklabels.split(";") classBreakLabels = breaklabels_list # Run the Renderer.breakCount function to use the classBreakValues # array parameters as the values, and create a counter. Renderer.breakCount = len(classBreakValues) i = 0 for brk in Renderer.classBreaks: brk.upperBound = float(classBreakValues[i]) #<-- Convert this to float arcpy.AddMessage(f'upper bound in symbology: {brk.upperBound}') brk.label = classBreakLabels[i] i+=1 layer.symbology = sym c+=1

Re: Custom script tool parameters will not accept decimals

JaredPilbeam2 — Fri, 22 Oct 2021 15:32:18 GMT

Interestingly, all I had to do was change arcpy.GetParameterAsText() to arcpy.GetParameter(). Then I didn't even have to bother with later changing the value to a float.