topic Re: How to solve this python question? I can't figure out at all...this one is stubbo in Python Questions

How to solve this python question? I can't figure out at all...this one is stubborn

PeterPete — Fri, 28 Feb 2014 23:09:54 GMT

def average_word_length(text):
    """ (list of str) -> float

    Precondition: text is non-empty. Each str in text ends with \n and at
    least one str in text contains more than just \n.

    Return the average length of all words in text. Surrounding punctuation
    is not counted as part of the words.

    >>> text = ['James Fennimore Cooper\n', 'Peter, Paul and Mary\n']
    >>> average_word_length(text)
    5.142857142857143
    """

Re: How to solve this python question? I can't figure out at all...this one is stubbo

CodyScott — Sun, 12 Dec 2021 04:39:13 GMT

def average_word_length(text):
    """ (list of str) -> float

    Precondition: text is non-empty. Each str in text ends with \n and at
    least one str in text contains more than just \n.

    Return the average length of all words in text. Surrounding punctuation
    is not counted as part of the words.

    >>> text = ['James Fennimore Cooper\n', 'Peter, Paul and Mary\n']
    >>> average_word_length(text)
    5.142857142857143
    """

I would approach it by first removing the '\n' from the string and removing the punctuation from the string.
After that, split the string by looking for the spaces in it, which should provide you with a tuple of each word in the string.
Then, loop each word getting its length and calculate an average from each word.

Here is a guess at the code below. I haven't tested this so who knows if the syntax is correct...
Also look here: http://stackoverflow.com/questions/12761510/python-how-can-i-calculate-the-average-word-length-in-a-sentence-using-the-spl
Best of luck!

text = ['James Fennimore Cooper\n', 'Peter, Paul and Mary\n']

for scen in text:
    string = scen.replace('\n','')
    #this would be any punctuation you want to replace
    string = string.replace("'","")

    #confirm syntax 
    string = string.split(' ')

    wordcount = len(string)
    wordlen = 0

    for word in string:
        tmplen = 0
        for letter in word:
            tmplen += 1
    
        wordlen += tmplen
    
    avglen = (wordcount/wordlen)

    print avglen

Re: How to solve this python question? I can't figure out at all...this one is stubbo

CodyScott — Sun, 12 Dec 2021 04:39:16 GMT

I would approach it by first removing the '\n' from the string and removing the punctuation from the string.
After that, split the string by looking for the spaces in it, which should provide you with a tuple of each word in the string.
Then, loop each word getting its length and calculate an average from each word.

Here is a guess at the code below. I haven't tested this so who knows if the syntax is correct...
Also look here: http://stackoverflow.com/questions/12761510/python-how-can-i-calculate-the-average-word-length-in-a-sentence-using-the-spl
Best of luck!
text = ['James Fennimore Cooper\n', 'Peter, Paul and Mary\n']

for scen in text:
    string = scen.replace('\n','')
    #this would be any punctuation you want to replace
    string = string.replace("'","")

    #confirm syntax 
    string = string.split(' ')

    wordcount = len(string)
    wordlen = 0

    for word in string:
        tmplen = 0
        for letter in word:
            tmplen += 1
    
        wordlen += tmplen
    
    avglen = (wordcount/wordlen)

    print avglen

Oh, if you had a ton of punctuation you wanted to get rid of everytime, write a function to parse the text and return the "stripped" version of your text

Re: How to solve this python question? I can't figure out at all...this one is stubbo

XanderBakker — Sun, 12 Dec 2021 04:39:19 GMT

You could use this:

def average_word_length(text):
    ''' Return the average length of all words in text. Do not
    include surrounding punctuation in words.
    text is a non-empty list of strings each ending in \n.
    At least one line in text contains a word.'''

    words = text.split()
    for word in words:
            average=sum(float(len(word)) for word in words)/float(len(words))
    return average

Sounds a lot like this post:
http://forums.arcgis.com/threads/103785-Hey-I-was-wondering-about-this-function-problem-for-a-while

... on comparing signatures ...

Kind regards,

Xander