topic Re: export to jpeg loop in Python Questions

export to jpeg loop

ReneSchulenberg — Fri, 30 Mar 2012 12:23:39 GMT

I created a loop to zoom to every shape in a shapefile and export that particular extent. The only problem is that the jpeg is given the number of the row as name. I want to give it the name of a field in de dbf. Does anybody have an idea how to do that?

import arcpy
from arcpy import env
from arcpy import mapping

mxd = arcpy.mapping.MapDocument(r"C:\gisbestanden\pythontest\test13.mxd")
df = arcpy.mapping.ListDataFrames(mxd)[0]

fc = r"Z:\kaarten\COROP\coropmultipart.shp"
count = str(arcpy.GetCount_management(fc))

x = 0

while x < int(count) + 1:
    rows = arcpy.SearchCursor(fc, "fid = " + str(x))
    for row in rows:
        xmin = row.shape.extent.XMin
        ymin = row.shape.extent.YMin
        xmax = row.shape.extent.XMax
        ymax = row.shape.extent.YMax
        df = arcpy.mapping.ListDataFrames(mxd)[0]
        newExtent = df.extent
        newExtent.XMin, newExtent.YMin = xmin, ymin
        newExtent.XMax, newExtent.YMax = xmax, ymax
        df.extent = newExtent
        mapping.ExportToJPEG(mxd, r"C:\gisbestanden\pythontest\gemeentekaart\JPEG_" + str(x) + ".jpg")

        print "successfully printed JPG"
    x += 1

Re: export to jpeg loop

curtvprice — Fri, 10 Dec 2021 22:27:37 GMT

I created a loop to zoom to every shape in a shapefile and export that particular extent. The only problem is that the jpeg is given the number of the row as name. I want to give it the name of a field in de dbf. Does anybody have an idea how to do that?

This is done the same way you accessed the shape field:

import arcpy
from arcpy import env
from arcpy import mapping

mxd = arcpy.mapping.MapDocument(r"C:\gisbestanden\pythontest\test13.mxd")
df = arcpy.mapping.ListDataFrames(mxd)[0]

fc = r"Z:\kaarten\COROP\coropmultipart.shp"  
count = str(arcpy.GetCount_management(fc))

x = 0

while x < int(count) + 1:
    rows = arcpy.SearchCursor(fc, "fid = " + str(x)) 
    for row in rows:
        xmin = row.shape.extent.XMin
        ymin = row.shape.extent.YMin
        xmax = row.shape.extent.XMax
        ymax = row.shape.extent.YMax
        # get the field contents to name the file
        filename = row.getValue("NAMEFIELD") # or: row.NAMEFIELD
        df = arcpy.mapping.ListDataFrames(mxd)[0]
        newExtent = df.extent
        newExtent.XMin, newExtent.YMin = xmin, ymin
        newExtent.XMax, newExtent.YMax = xmax, ymax
        df.extent = newExtent
        # use the field contents in the filename
        mapping.ExportToJPEG(mxd, 
             r"C:\gisbestanden\pythontest\gemeentekaart\JPEG_{0}.jpg".format(filename))

        print "successfully printed JPG"
    x += 1

Re: export to jpeg loop

ReneSchulenberg — Fri, 30 Mar 2012 12:56:55 GMT

thanks for the quick reply! It worked!!

Re: export to jpeg loop

nathanbush — Tue, 03 Mar 2015 18:57:09 GMT

Hi Curtis,

I'm new to Python, but this is exactly what I need to do - run through my shapefile (poly) and zoom to each polygon within and export to JPEG. I've copied your script, but keep getting the attribute error 'Extent' object has no attribute 'Xmin'. My shapefile consists of 4 fields (FID, Shape, Unit, Hectares), am I missing something?

Nate