topic Re: Clipping a raster and renaming it in Python Questions

Clipping a raster and renaming it

RileyCotter — Mon, 01 Apr 2013 21:36:15 GMT

I am still pretty much a beginner when it comes to python, so go easy on me. I am trying to clip a raster to a tiled polygon layout. I have a feeling that my errors: ERROR 000628: Cannot set input into parameter rectangle. and Error 000622 are happening when I am trying to use the geometry of one feature to clip my raster, and then renaming it to that tile name in the "text" field.

Any help would be much appreciated, and please let me know if anything needs to be clarified.

Thanks!!

desc = arcpy.Describe(DEMpoly) shapefieldname = desc.shapeFieldName  rowCursor = arcpy.SearchCursor(DEMpoly)  for row in rowCursor:     feat = row.getValue(shapefieldname)     arcpy.Clip_management(OUTraster, feat, row.getValue(Text) + ".img")     cursor.next()

Re: Clipping a raster and renaming it

RileyCotter — Mon, 01 Apr 2013 22:19:28 GMT

fixed it.....just had my input and output values for the clip tool all messed up

for row in rowCursor:     feat = row.getValue(shapefieldname)     arcpy.Clip_management(OUTraster, "#", row.getValue(field) + ".img", feat, "0", "ClippingGeometry")     rowCursor.next()

Re: Clipping a raster and renaming it

curtvprice — Sun, 12 Dec 2021 02:58:12 GMT

Since you're new to Python, I thought I'd show you how formatting strings help with the syntax.
Much easier to debug when a SQL expression or pathname gets complicated!

for row in rowCursor:
    feat = row.getValue(shapefieldname)
    clipRas = "{0}.img".format(row.getValue(field))
    arcpy.Clip_management(OUTraster, "#", clipRas, feat, "0", "ClippingGeometry")
    rowCursor.next()