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JoshTownsend — Wed, 01 Aug 2012 12:23:42 GMT

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Re: Extracting file name without extension.

MathewCoyle — Wed, 01 Aug 2012 12:48:45 GMT

As seen here.
http://stackoverflow.com/questions/678236/how-to-get-the-filename-without-the-extension-from-a-path-in-python

os.path.splitext(os.path.basename(fc))[0]

Re: Extracting file name without extension.

PeterWilson — Sat, 17 Aug 2013 19:20:07 GMT

thanks Mathew, the following was helpful.

Regards

Re: Extracting file name without extension.

curtvprice — Sun, 12 Dec 2021 00:23:39 GMT

Here's a fixed version of Josh's code...

import win32com.client, sys, string, os
gp = win32com.client.Dispatch("esriGeoprocessing.gpDispatch.1")
gp.workspace = " ...  "
try:
    fcs = gp.ListFeatureClasses("*", "all")
    fc = fcs.Next()
    while fc:
        gp.AddField_management (fc, "FILENAME", "TEXT", "", "", "50")
        fcName = os.path.splitext(fc)[0]
        gp.CalculateField_management (fc, "FILENAME", fcName)
        fc = fcs.Next()
except:
    print gp.GetMessages ()

For the archive, the above is ArcGIS 9.2 syntax, and requires PythonWin to be installed (for the win32com import).

For people who are at 10.0 or later, the way to do this would be something like this.
Note I modified Calculate Field to use the Python parser instead of VBScript.

import arcpy
arcpy.env.workspace = " ...  "
try:
  fcs = arcpy.ListFeatureClasses("*", "all")
  for fc in fcs:
    arcpy.AddField_management(fc, "FILENAME", "TEXT", "", "", "50")     
    fcName = os.path.splitext(fc)[0]
    arcpy.CalculateField_management(fc, "FILENAME", "'{0}'".format(fcName), "PYTHON_9.3")
except:
  print arcpy.GetMessages()

[thread=48475]Please read: how to post Python code[/thread]

I would be remiss not to mention that this sort of thing is also pretty easy to do with ModelBuilder 10.0 iterators.

topic Re: Extracting file name without extension. in Python Questions

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Re: Extracting file name without extension.

Re: Extracting file name without extension.

Re: Extracting file name without extension.