Lable Expression for relationship featureclasss

LarryAdgate — Tue, 24 Nov 2015 19:29:37 GMT

This label expression below works along with a relationship class attachment linked to a line feature class. It only works great when the Domain setup for the Field "DIAMETER" does not include an inch the character. My domain for "DIAMETER" currently reads: 2,3,4&6 but it needs to be corrected to read 2",3"4" & 6". When applying the inch character(") to the domain the script errors. Can someone help me with this?

Thanks,

Larry

Function FindLabel ( [DIAMETER] , [LINETYPE] )

FindLabel = ""

if [DIAMETER] AND [LINETYPE] = "Fire Service" then

FindLabel = [DIAMETER] & "" & "FS"

end if

if [DIAMETER] AND [LINETYPE] = "Domestic" then

if FindLabel = "" then

FindLabel = [DIAMETER] & "" & "DS"

end if

if [DIAMETER] AND [LINETYPE] = "Irrigation" then

if FindLabel = "" then

FindLabel = [DIAMETER] & "" & "IRR"

end if

if [DIAMETER] AND [LINETYPE] = "Air Valve" then

if FindLabel = "" then

FindLabel = [DIAMETER] & "" & "AV"

end if

if [DIAMETER] AND [LINETYPE] = "Sampling Station" then

if FindLabel = "" then

FindLabel = [DIAMETER] & "" & "SS"

end if

End Function

Re: Lable Expression for relationship featureclasss

mneer — Tue, 24 Nov 2015 21:16:03 GMT

I had asked something similar in maybe this will help you?

Re: Double Quote in Label Expression

topic Lable Expression for relationship featureclasss in Python Questions

Lable Expression for relationship featureclasss

Re: Lable Expression for relationship featureclasss