How do I dynamically define an output feature class using variables

LauraBlackburn — Thu, 08 Jan 2015 17:15:41 GMT

I am creating code to loop through feature classes in a folder and run the fishnet process. I am trying to define the output feature class so that it is a combination of the input feature class and the scale used. Here's what I have so far....any help is greatly appreciated as this is all new to me.

# Import arcpy module

import arcpy, os, sys, traceback

# Set the necessary product code

import arceditor

import arcinfo

# set workspace path for block location

aDataPath = 'F:\\Workspace\\Sandy\\GM_costAnalysis\\analysis2\\'

arcpy.env.workspace = 'F:\\Workspace\\Sandy\\GM_costAnalysis\\analysis2\\'

# Set datapath for grid files

bDataPath = 'F:\\Workspace\\Sandy\\GM_costAnalysis\\analysis2\\6K\\'

# Set Geoprocessing environments

arcpy.env.snapRaster = ""

# Create a list of cell sizes

scaleList = [6000, 4000, 3000, 2000, 1000, 500]

# Create a list of searching radii

radiusList = ["3000 Meters", "2000 Meters", "1500 Meters", "1000 Meters", "500 Meters"]

# Step 1 - loop through each block and do the following processes at all grid scales

try:

# Create List of feature classes starting with 'B' - all the block layers

fc_list = arcpy.ListFeatureClasses("B*")

for fc in fc_list:

# Process: Create Fishnet

# Create a describe object from the feature class

desc = arcpy.Describe(fc)

for scale in scaleList:

# Define Fishnet Output Name

Output_Grid_Name =bDataPath + scale + fc

tempEnvironment0 = arcpy.env.extent

arcpy.env.extent = desc.extent.XMin, desc.extent.XMax, desc.extent.YMin, desc.extent.YMax

arcpy.CreateFishnet_management(Output_Grid_Name, desc.extent.XMin desc.extent.YMin, desc.extent.Xmin desc.extentXMax, scale, scale, "0", "0", desc.extent.XMax desc.extent.YMax, "LABELS", fc, "POLYGON")

arcpy.env.extent = tempEnvironment0

except:

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How do I dynamically define an output feature class using variables