topic Re: Can I filter a FeatureLayer by a custom geometry in ArcGIS Web AppBuilder Questions

Can I filter a FeatureLayer by a custom geometry

deleted-user-RhG9zFDAFTI1 — Wed, 28 Mar 2018 10:09:07 GMT

Hi I'm using ArcGIS JS API 3.21 and Web Appbuilder for Developers 2.7.

I'm defining and adding a feature layer from a map service to my map, giving it a custom unique value renderer and setting a definition expression and it is working fine. The final thing I need to do is to filter it by a custom polygon geometry. In the service you can pass custom geometry to a query, I just need to find out how to set a filter on my feature layer using the same geometry.

I've tried using MODE_SELECTION and then selecting features with the geometry, but this gets rid of my unique value renderer in favour of the selection symbol. I'm pretty sure I can't set a unique value renderer as the selection symbol and even then that would be a bit hacky.

The user needs to generate a custom selection of features from the map using attribute filtering and custom polygon filtering, and once they are happy with their selection the features are submitted via a HTTP request to an ordering system. The user only wants their currently selected features to appear on the map.

Something like this would be good:

var featureLayer = new FeatureLayer(layerUrl, {

mode: FeatureLayer.MODE_SNAPSHOT,

outFields: [field],

id: OverLayerID,

showAttribution: false

});

featureLayer.setRenderer(renderer);

featureLayer.setDefinitionExpression(expr);

featureLayer.setInputGeometry(geometry); <------ something like this would be perfect

this.map.addLayer(featureLayer);

The featurelayer definition expression and input geometry can be updated on the fly as the user interacts with the widget.

Any suggestions would be appreciated.

Thanks

Mike.

Re: Can I filter a FeatureLayer by a custom geometry

RobertScheitlin__GISP — Wed, 28 Mar 2018 13:38:11 GMT

Mike,

Your workflow should be do a queryIds on the FeatureLayer to get the ids that the geometry intersect with and then use the FeatureLayers setDefinitionExpression using a sql statement like ObjectID IN (your results from the Ids query array.join()).

Re: Can I filter a FeatureLayer by a custom geometry

deleted-user-RhG9zFDAFTI1 — Thu, 29 Mar 2018 00:18:26 GMT

Hi Robert,

Thanks for getting back to me. The feature layer that they are doing their selection on has many thousands of features that are densely packed. Is there a limit to the length of the definition expression that I can use, as the number of selected features have the potential to be quite large.

Thanks

Re: Can I filter a FeatureLayer by a custom geometry

RobertScheitlin__GISP — Thu, 29 Mar 2018 12:58:22 GMT

Mike,

That is exactly the situation that the SQL Syntax ObjectID IN (x,y,z) is capable of handling.