<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" version="2.0">
  <channel>
    <title>topic Re: can I set up default time? in ArcGIS Survey123 Questions</title>
    <link>https://community.esri.com/t5/arcgis-survey123-questions/can-i-set-up-default-time/m-p/1174551#M42771</link>
    <description>&lt;P&gt;Hi Kerry&lt;/P&gt;&lt;P&gt;Yes - what you can do is use the today() function - this gives you the current date at midday 12 o'clock&lt;/P&gt;&lt;P&gt;To get to 8:30am you subtract 12 and add 8 and a half hours:&lt;/P&gt;&lt;P&gt;today()+(-12+8.5)*60*60*1000&lt;/P&gt;&lt;P&gt;Hope that helps&lt;/P&gt;</description>
    <pubDate>Tue, 17 May 2022 14:11:38 GMT</pubDate>
    <dc:creator>DeonLengton</dc:creator>
    <dc:date>2022-05-17T14:11:38Z</dc:date>
    <item>
      <title>can I set up default time?</title>
      <link>https://community.esri.com/t5/arcgis-survey123-questions/can-i-set-up-default-time/m-p/1174377#M42758</link>
      <description>&lt;P&gt;Hello,&amp;nbsp;&lt;/P&gt;&lt;P&gt;Is there a way that I can set up default time? For example, I want to make 'from' date/time question always indicate current date/8:30 am. If I use today() it shows 12am as default time, and if I use now() it will pick up the current time. Thank you.&lt;/P&gt;&lt;P&gt;Kerry&lt;/P&gt;</description>
      <pubDate>Mon, 16 May 2022 22:26:54 GMT</pubDate>
      <guid>https://community.esri.com/t5/arcgis-survey123-questions/can-i-set-up-default-time/m-p/1174377#M42758</guid>
      <dc:creator>KerryKang</dc:creator>
      <dc:date>2022-05-16T22:26:54Z</dc:date>
    </item>
    <item>
      <title>Re: can I set up default time?</title>
      <link>https://community.esri.com/t5/arcgis-survey123-questions/can-i-set-up-default-time/m-p/1174551#M42771</link>
      <description>&lt;P&gt;Hi Kerry&lt;/P&gt;&lt;P&gt;Yes - what you can do is use the today() function - this gives you the current date at midday 12 o'clock&lt;/P&gt;&lt;P&gt;To get to 8:30am you subtract 12 and add 8 and a half hours:&lt;/P&gt;&lt;P&gt;today()+(-12+8.5)*60*60*1000&lt;/P&gt;&lt;P&gt;Hope that helps&lt;/P&gt;</description>
      <pubDate>Tue, 17 May 2022 14:11:38 GMT</pubDate>
      <guid>https://community.esri.com/t5/arcgis-survey123-questions/can-i-set-up-default-time/m-p/1174551#M42771</guid>
      <dc:creator>DeonLengton</dc:creator>
      <dc:date>2022-05-17T14:11:38Z</dc:date>
    </item>
  </channel>
</rss>

