topic Re: UniqueValueRender for n values in a GraphicLayer in ArcGIS Runtime SDK for WPF (Retired) Questions

UniqueValueRender for n values in a GraphicLayer

Cristian_Galindo — Wed, 09 Apr 2014 19:38:20 GMT

DEAR PEOPLE FROM THE FUTURE: Here's what we've figured out so far???

I have a GraphicsLayer, it has n objects in the Graphics property. I want to use a UniqueValueRenderer for this layer.

I had use this kind of approach with an ArcGISLocalFeatureLayer and the GenerateRendererTask, but the GenerateRendererTask object requires an URL, it the used approach I used the service URL from the ArcGISLocalFeatureLayer. but a GraphicsLayer, it is not attached to a service.

can I use this task to generate the render based in a ColorRamp for a Graphicslayer?

If I have to iterate over each one of the grpahics in the layer to create the simbols, Can i use color ramp to calculate the color?

thanks!!

Re: UniqueValueRender for n values in a GraphicLayer

Cristian_Galindo — Wed, 09 Apr 2014 20:07:08 GMT

Ok fellows, i got it :

            var uniqueValueRenderer = new UniqueValueRenderer();             var defaultSymbol = new ESRI.ArcGIS.Client.Symbols.SimpleLineSymbol { Width = 2.5 };             uniqueValueRenderer.DefaultSymbol = defaultSymbol;             uniqueValueRenderer.Field = attributeField; //parameter              var colorRange = new ColorRange                                  {                                      From = this.GetRandomColor(),                                      To = this.GetRandomColor()                                  };              var rampInterpolator = new RampInterpolator                                        {                                            ColorRange = colorRange                                        };              foreach (var graphic in layer.Graphics)             {                 var valueInfo = new UniqueValueInfo                                     {                                         Label = graphic.Attributes[attributeField].ToString(),                                         Value = graphic.Attributes[attributeField].ToString(),                                         Symbol =                                             rampInterpolator.GetInterpolatedSymbol(                                                 defaultSymbol, graphic, 0, layer.Graphics.Count, layer.Graphics.IndexOf(graphic))                                     };                 uniqueValueRenderer.Infos.Add(valueInfo);             }             return uniqueValueRenderer

Re: UniqueValueRender for n values in a GraphicLayer

MichaelBranscomb — Thu, 10 Apr 2014 07:49:05 GMT

Hi,

If you do have services in your solution, you can use the GenerateRendererTask to create your renderer, even for a GraphicsLayer. The renderer it returns does not have to be related to the actual data in the service I believe.

Cheers

Mike

Re: UniqueValueRender for n values in a GraphicLayer

MichalKowalczuk — Fri, 11 Apr 2014 23:09:29 GMT

If you do have services in your solution, you can use the GenerateRendererTask to create your renderer, even for a GraphicsLayer.

Hi,
If above is true, what should I pass to Url property when I want to create renderer for a GraphicsLayer. I didn't find this case in API reference and samples.

Mike

Re: UniqueValueRender for n values in a GraphicLayer

MichaelBranscomb — Mon, 14 Apr 2014 06:10:19 GMT

Hi,

Sorry for the incorrect information - I thought the it was possible to use the GenerateRendererTask independently of the layers within a service by specifying some additional values but it does appear to only work against the source data. It does however work with both the original service layers and additional layers defined through the DynamicLayer capability.

Cheers