topic Re: Is there a way to open an existing layout programmatically? in ArcGIS Pro SDK Questions

Is there a way to open an existing layout programmatically?

AnthonyMikelson — Thu, 30 Jul 2015 13:18:55 GMT

From the layout snippets and examples provided I understand how to get a reference to an existing layout, but is there a way to also open it programmatically?

Re: Is there a way to open an existing layout programmatically?

JeffBarrette — Thu, 30 Jul 2015 18:54:39 GMT

There is currently not a way to open a layout yet but there will be.

Re: Is there a way to open an existing layout programmatically?

AnthonyMikelson — Thu, 30 Jul 2015 19:14:49 GMT

Will there be a way to obtain the existing layouts much like the way we can retrieve layers?

Example:
MapView activeView = MapView.Active;

IReadOnlyList<Layer> allMapLayers = activeView.Map.GetLayersAsFlattenedList();

Project project = Project.Current;

IReadOnlyList<Layout> allLayouts = project.GetLayoutsAsFlattenedList();

IReadOnlyList<LayoutProjectItem> allLayouts = project.GetLayoutItemsAsFlattenedList();

Re: Is there a way to open an existing layout programmatically?

CharlesMacleod — Fri, 07 Aug 2015 19:33:50 GMT

FYI: You will need to add a reference to ArcGIS.Desktop.Layouts.

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using ArcGIS.Desktop.Core;

using ArcGIS.Desktop.Framework;

using ArcGIS.Desktop.Framework.Contracts;

using ArcGIS.Desktop.Framework.Dialogs;

using ArcGIS.Desktop.Framework.Threading.Tasks;

using ArcGIS.Desktop.Layouts; <-- add the ArcGIS.Desktop.Layouts.dll to your references

namespace ProAppModule4 {

internal class Button1 : Button {

protected async override void OnClick() {

var layouts = Project.Current.GetItems<LayoutProjectItem>();

StringBuilder sb = new StringBuilder();

sb.AppendLine("Layouts:");

await QueuedTask.Run(() => {

foreach (var layoutItem in layouts) {

var layout = layoutItem.GetLayout();

sb.AppendLine(string.Format("\t{0}", layout.Name));

//etc

}

});

MessageBox.Show(sb.ToString());

}