topic Re: How to access layer using feature service URL/path in ArcGIS API for Python Questions

How to access layer using feature service URL/path

ZacharyKasson — Thu, 28 Sep 2023 00:10:14 GMT

Hey there,

I am trying to access a feature layer within my portal using the layers path. I have been accessing the data within visual studio code using the feature layers ID like this:

feature_service_layer = gis.content.get('964b4b7b112347e9ff76609bfc75432').layers[0]

I'd like to make a Geo Processing tool out of the code. The tool would accept the parameter under the format of the URL which would be something along the lines of: 'https://maps.portaladdress.com/arcgis/rest/services/Hosted/Feature_layer/FeatureServer/0'

I have tried to add the url to the code but it is unsuccessful. Here is what it looked like (I also tried the .Search method):

feature_service_layer = gis.content.get(https://maps.portaladdress.com/arcgis/rest/services/Hosted/Feature_layer/FeatureServer/0) feature_service_layer = gis.content.search(https://maps.portaladdress.com/arcgis/rest/services/Hosted/Feature_layer/FeatureServer/0)

If I can't use these methods how am I supposed to take a feature layer in as a parameter and access its data?

Any help is appreciated.

Thanks!

Re: How to access layer using feature service URL/path

ZacharyKasson — Thu, 28 Sep 2023 00:17:36 GMT

Update,

I have found that this actually does work :

feature_service_layer = gis.content.search('https://maps.portal.com/arcgis/rest/services/Hosted/feature_layer/FeatureServer')

But it gives me the content as a a list which has proven hard to get to a sdf.

I tried :

sdf = pd.DataFrame.spatial.from_layer(feature_service_layer[0])

but received this error:

Traceback (most recent call last): File "y:\Zack\Other_Projects\Python_projects\Duplicate Stand ID Tool\id_duplicate_tool_featureservice.py", line 33, in <module> sdf = pd.DataFrame.spatial.from_layer(feature_service_layer[0]) File "C:\Program Files\ArcGIS\Pro\bin\Python\envs\arcgispro-py3\lib\site-packages\arcgis\features\geo\_accessor.py", line 3077, in from_layer raise Exception("Could not load the dataset: %s" % str(e)) Exception: Could not load the dataset: 'Item' object has no attribute 'filter' PS Y:\Zack\Other_Projects\Python_projects\Duplicate Stand ID Tool>

Re: How to access layer using feature service URL/path

EarlMedina — Thu, 28 Sep 2023 14:09:53 GMT

Have you considered just using FeatureLayer? If you know ahead of time what the URL is, you don't have to search for it.

from arcgis import GIS from arcgis.features import FeatureLayer gis = GIS() url = "https://urlforlayer/0" fl = FeatureLayer(url, gis)

Re: How to access layer using feature service URL/path

ZacharyKasson — Thu, 28 Sep 2023 15:16:05 GMT

I tried that. Similar issue. I can access the layer but not the table.

feature_service_item = arcgis.features.FeatureLayer('https://maps.url.com/arcgis/rest/services/Hosted/FL/FeatureServer') print(feature_service_item) sdf = pd.DataFrame.spatial.from_layer(feature_service_item)

Returns

Exception: Could not load the dataset: Cannot perform query. Invalid query parameters.

Re: How to access layer using feature service URL/path

maile — Tue, 12 Mar 2024 14:00:22 GMT

Hi, there is a section on the site featurelayercollection , that will solve your problem.

Example:

You already know the url of the feature service and login credentials

url = 'https://maps.portaladdress.com/arcgis/rest/services/Hosted/Feature_layer/FeatureServer' portalUrl = 'https://maps.portaladdress.com/portal/' portalUser = 'portaladmin' portalPassw = 'xxxxxxxxxx'

GIS login

from arcgis.gis import GIS gisP = GIS(portalUrl, portalUser, portalPassw)

and you have access to layers and tables in the feature service

from arcgis.features import FeatureLayerCollection flc=FeatureLayerCollection(url, gisP) print(flc.layers) # or flc.tables

and you can continue processing

for item in flc: print(item.url) ...