topic Re: Get User Folder Name Provided the Folder ID in ArcGIS API for Python Questions

Get User Folder Name Provided the Folder ID

mpboyle — Tue, 09 Jul 2019 14:18:53 GMT

Using the ArcGIS API for Python, is there a way to get the name of a user's folder if provided the folder ID?

For example, one of the properties of a portal item is "ownerFolder", which returns the id of the user's folder where the portal item is housed. This is very helpful if the user has many folders when trying to find the item. I'd like to know the name of this folder rather than just having the id. Is there something similar to "content.get('item_id')" that can be used to return folder properties?

I'm aware of arcgis.gis.User("user_name").folders ... which returns a list of dictionaries providing information about all the folders a user has. I don't really want to cross-reference all the user's folders and then match the id, but if that's the only way...

Re: Get User Folder Name Provided the Folder ID

TregChristopher — Tue, 20 Aug 2019 19:21:58 GMT

Here's how I did it:

gis = GIS(urlAGOL, userName, userPass)

gisUser = arcgis.gis.User(gis, "username of person who owns folder")
for fld in gisUser.folders:
print(fld['id'], fld['title'])

Re: Get User Folder Name Provided the Folder ID

AndresCastillo — Mon, 27 May 2024 21:46:02 GMT

https://support.esri.com/en-us/knowledge-base/retrieve-the-folder-name-in-which-a-certain-item-exists-000028966

Re: Get User Folder Name Provided the Folder ID

kurtia — Mon, 24 Nov 2025 19:54:42 GMT

# GIS Connection gis = GIS(portalurl,username,password,verify_cert=False) # Get user and folders (user = gis.users.get(owner)) user = gis.users.get(username) source_folders = user.folders for folder in source_folders: # Access properties using dot notation for 'title' logger.info(f"Folder Name: {folder.name}") # If you need to see all available attributes, you can print dir(folder) # print(dir(folder))

Re: Get User Folder Name Provided the Folder ID

Joshua-Young — Thu, 29 Jan 2026 23:45:29 GMT

@kurtia thank you for the example code. I used to use folder['title'] in my scripts and now that no longer works. Apparently folder.name is the way to do it now.