topic Define layer name with sdf.spatial.to_featurelayer() in ArcGIS API for Python Questions

Define layer name with sdf.spatial.to_featurelayer()

DavinShokes1 — Thu, 20 Jun 2024 13:29:23 GMT

I am looking at the documentation for "to_featurelayer()" at

https://developers.arcgis.com/python/api-reference/arcgis.features.toc.html?highlight=to_featurelayer#arcgis.features.GeoAccessor.to_featurelayer

However, I can't figure out how to name the feature layer.

# Overwrite layer 0 service1 = {'featureServiceId':'**unspecified**', 'layer':0} pub_sdf1 = sdf1.spatial.to_featurelayer(title='Testing_data',gis=gis, tags=['VM'], sanitize_columns=True,overwrite=True, service=service1) # Overwrite layer 1 service2 = {'featureServiceId':'**unspecified**', 'layer':1} pub_sdf2 = sdf2.spatial.to_featurelayer(title='Testing_data',gis=gis, tags=['VM'], sanitize_columns=True,overwrite=True, service=service2)

This code succeeds in overwriting the feature layers from spatial dataframe. However, both feature layers are called the same thing now.

Thank you.

Re: Define layer name with sdf.spatial.to_featurelayer()

ChrisCowin_dhs — Fri, 28 Jun 2024 21:51:05 GMT

Are you not explicitly naming them the same thing by using the same title?

Re: Define layer name with sdf.spatial.to_featurelayer()

DavinShokes1 — Mon, 08 Jul 2024 17:09:07 GMT

The title seems to be title to the Item name and not the layer name.

I ended up using a going a different route for overwritting my layers. To_featurelayer() is missing too much documentation (such as the fact that a new shapefile is made from the dataframe and that is what is published).

Thanks for the help.