topic Re: ArcGIS JS Portal Login in ArcGIS JavaScript Maps SDK Questions

ArcGIS JS Portal Login

Wade — Sat, 26 Feb 2022 10:27:20 GMT

When I set the portal, the layer is private in ArcGIS Enterprise, the login screen appears, how to log in it in the application?

require([ "esri/config" ], function ( esriConfig ) { esriConfig.portalUrl = "https://MyApp/portal/"; });

Re: ArcGIS JS Portal Login

GaryB — Sat, 26 Feb 2022 23:29:45 GMT

Hi Wade, this link may help with what you are trying to do: https://developers.arcgis.com/javascript/latest/arcgis-organization-portals/

Re: ArcGIS JS Portal Login

Wade — Sun, 27 Feb 2022 10:10:44 GMT

Hi GaryB

The document describes the ArcGIS Enterprise part, not very clear, is there a practical example?

Re: ArcGIS JS Portal Login

GaryB — Sun, 27 Feb 2022 14:45:15 GMT

yes, I recall struggling with this a bit, try this:

let info = new OAuthInfo({appId: 'xxxxxxxxxxxxxxxx', portalUrl: 'https://my.portal.url/portal', popup: false}) esriId.registerOAuthInfos([info]) esriId.checkSignInStatus(info.portalUrl + '/sharing').then(function () { let portal = new Portal({url: 'https://my.portal.url/portal'}) portal.authMode = 'immediate' portal.load().then( function () { console.log(portal.user.username + ' is now connected to the portal') // call my afterSuccessfulLogin function }, function (error) { console.log("couldn't successfully load the portal") } ) })

Re: ArcGIS JS Portal Login

Wade — Tue, 01 Mar 2022 02:15:08 GMT

ArcGIS Enterprise can also create appId?

The current way is to use ArcGIS Server generate token for verification.

Re: ArcGIS JS Portal Login

Lerman — Mon, 07 Mar 2022 07:21:52 GMT

Hello GaryB, I tested this method, but the user still needs to log in once. Is there a solution to build the identity information into the program without requiring the user to log in again? Thank you so much!

Re: ArcGIS JS Portal Login

Wade — Thu, 16 Nov 2023 03:37:58 GMT

Hi @GaryB, I tested this method, but the user still needs to log in once. Is there any example, using the token method, the user does not need to log in once ?