topic Re: Definition Expression Issue in ArcGIS JavaScript Maps SDK Questions

Definition Expression Issue

AndrewMurdoch1 — Wed, 09 Aug 2023 18:00:47 GMT

Good Day

I'm using "@arcgis/core": "4.27.6"

I think I found a bug in the querying logic when setting a definition expression (DE). Assume I have a layer and I set the DE to 'a = 1 OR a =2', and two of the X features are now shown.

If I run another query on the map: 'a = 3', and get back a feature / geometry, why is the visible flag still true when the feature isn't visible? Should I be able to use a DE as a first pass filter that's constant, and then on top of that apply more filters using queries?

This is a code sample of what I'm doing:

Definition Expression Stage, assume query: 'a = 1 OR a = 2':

this._view?.map?.layers?.forEach((layer) => { if (layer?.type === 'feature' && !layer?.id.includes('meta-')) { layer.definitionExpression = query; } }

Running the second query, assume mapQuery is: 'a = 3':

When I look for anything but a 1 or 2, they aren't visible on the map, so that flag shouldn't be set.

Thanks

Re: Definition Expression Issue

JoelBennett — Wed, 09 Aug 2023 19:02:17 GMT

The visible property for graphics that come from a FeatureLayer is pretty much meaningless; it's really only useful for graphics in GraphicsLayers.

Your query is also being sent to the service to be executed, and it returns all features that match. Because the conditions of the DE are not included, it therefore returns features 1 and 2 also. If you want the conditions of the DE to be included, you should use createQuery, and then modify the where clause with the additional conditions.

Alternatively, if you just want to query the layer on the client side, which will honor your DE, then you can use queryFeatures on the layer's LayerView.

Re: Definition Expression Issue

AndrewMurdoch1 — Wed, 09 Aug 2023 19:45:59 GMT

Thanks! That did exactly what I wanted 🙂