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I called ESRI Support and found out that there are some inconstancy for this Widget. For the first time query, the selected data will appear in a new table which will be at the first from the left. For the second time query, the selected data will not appear by itself. After the query, you need to open Layer List, open the pulldown menu of the _Query Result Layer, and select Open Attribute Table. The selected data will appear in a new table which will be at first from the right. For the third time and later query, the same things have to be done for the second time. But the new table is blank. You have to click the Refresh button at the top of the table, then the new selection will appear in the new table. This is sort of confusing. 😞
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03-23-2015
02:01 PM
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Oh I see. I will report this. Thank you for your help.
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03-23-2015
10:07 AM
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Thank you very much for your help. I checked the box, and it worked at the first time. The new tab was added and contains the result of the selection, which is good. But it does not work in the same way after the second try. Nothing was selected. I am not sure why.
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03-23-2015
09:53 AM
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I have a question regarding Query Widget of the WebApp. I made a web application using WebApp, and put a Query widget in it. The Query seems like working, because if I select parcels using Query, the selected parcels appear in the right pane of the Query. But if I open the table of the selected data, it still says that “0 selected”. Is there any way that I can select data from the table using Query widget?
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03-20-2015
12:24 PM
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Thank you for the reply. I tried, but am still getting an error message like the below. Traceback (most recent call last): File "Q:\GIS_Tools\HeatMapTool\Python\HeatMapTool_Incidents_Add_Reclass_para5_revised_072414.py", line 149, in <module> arcpy.MakeRasterLayer_management(heatMapTest2, layername) File "c:\program files (x86)\arcgis\desktop10.2\arcpy\arcpy\management.py", line 6479, in MakeRasterLayer raise e ExecuteError: ERROR 000582: Error occurred during execution. Failed to execute (HeatMapAllWithOutputLayerParaRevised072414). Failed at Thu Jul 24 17:43:35 2014 (Elapsed Time: 14.72 seconds)
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07-24-2014
02:47 PM
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I have a question regarding Python script for making a Heat Map Tool. I am making a Heat Map Tool where users can set the map extent, the tool will read the current scale of the map, then make a raster heat map layer using appropriate cell size and search radius depend on the map scale, and the new raster layer will appear on the TOC of the map document. I succeeded this part. But I also put a function that users can set the raster name, and the name will appear as a layer name too. The script is the below. # Script arguments heatMapTest2 = Output_Raster_Layer heatMapTest2Name = 'Output Raster' templist = heatMapTest2.split("\\") layername = templist[-1] MXD = arcpy.mapping.MapDocument("CURRENT") dataFrame = arcpy.mapping.ListDataFrames(MXD)[0] mapExtent = dataFrame.extent scale = dataFrame.scale Input_Layer_2 = Input_Layer #Add new layer to the dataframe result = arcpy.MakeRasterLayer_management(heatMapTest2, layername) lyrLayer = result.getOutput(0) arcpy.mapping.AddLayer(dataFrame, lyrLayer, "AUTO_ARRANGE") This function does work if I use the ArcGIS from the remote, and the work environment is the same server as the remote. But I set the work environment in different server, it gives me an error message as the below. Traceback (most recent call last): File "Q:\GIS_Tools\HeatMapTool\Python\HeatMapTool_Incidents_Add_Reclass_para5_short.py", line 149, in <module> result = arcpy.MakeRasterLayer_management(heatMapTest2, layername) File "c:\program files (x86)\arcgis\desktop10.2\arcpy\arcpy\management.py", line 6479, in MakeRasterLayer raise e ExecuteError: ERROR 000582: Error occurred during execution. Failed to execute (HeatMapAllWithOutputLayerPara). (line 149 is result = arcpy.MakeRasterLayer_management(heatMapTest2, layername)) Is there anybody who can tell why that happened?
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07-22-2014
03:07 PM
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